8-inch slab equation check
Use ZR = −1.282, S0 = 0.35, ΔPSI = 2.0, pt = 2.5, Sc = 690 psi, Ec = 4,000,000 psi, k = 100 pci, J = 3.2 and Cd = 1.0. D = 8 in (20.32 cm) gives log₁₀W18 = 6.421672, or 2.640413 million ESALs.
Add one row per truck type. Each truck can have multiple axle groups (single, tandem, triple). LEFs are interpolated live from AASHTO Tables D.10–D.18. Each truck's Adopted Factor starts synced to its computed Composite LEF; setting it higher implies truck loading and/or tyre pressure above the adopted standard/reference conditions.
Note: setting an Adopted value higher than the computed composite LEF implies truck loading and/or tyre pressure above the adopted standard/reference conditions.
| Truck Type | Front Axle | Mid. Axle | Rear1 Axle | Rear2 Axle | Total | Adopted | AADT | Daily ESAL | ||
|---|---|---|---|---|---|---|---|---|---|---|
| Total Daily ESAL | — | |||||||||
| Total Annual ESAL | — | |||||||||
| Growth to opening year (1+g)p | — | |||||||||
| Growth Factor over the design life, GF | — | |||||||||
| Design lane factor DDF × LDF | — | |||||||||
| Design-lane ESALs over the design life, millions | — | |||||||||
| Year | Calendar | Annual ESALs | Cumulative, design lane from opening |
|---|
Evaluate the AASHTO 1993 concrete-pavement equation and compare trial and required slab thickness.
Slab depth displayed in cm, converted to inches internally; Sc and Ec in psi; k in pci; traffic in millions of ESALs.
The 1993 empirical equation is solved on its physically relevant branch. Enter project-specific flexural strength and effective foundation k where available. The optional CBR and layer-factor estimates are simplified assumptions, not the full AASHTO seasonal support procedure.
Illustrative inputs for checking the method; these are not project records.
Use ZR = −1.282, S0 = 0.35, ΔPSI = 2.0, pt = 2.5, Sc = 690 psi, Ec = 4,000,000 psi, k = 100 pci, J = 3.2 and Cd = 1.0. D = 8 in (20.32 cm) gives log₁₀W18 = 6.421672, or 2.640413 million ESALs.
Use ZR = −1.282, S0 = 0.35, ΔPSI = 2.0, pt = 2.5, Sc = 690 psi, Ec = 4,000,000 psi, k = 100 pci, J = 3.2 and Cd = 1.0. D = 10 in (25.40 cm) gives log₁₀W18 = 7.031208, or 10.745030 million ESALs.
Evaluate the AASHTO 1993 concrete-pavement equation and compare trial and required slab thickness.
Slab depth displayed in cm, converted to inches internally; Sc and Ec in psi; k in pci; traffic in millions of ESALs. The 1993 empirical equation is solved on its physically relevant branch. Enter project-specific flexural strength and effective foundation k where available. The optional CBR and layer-factor estimates are simplified assumptions, not the full AASHTO seasonal support procedure.
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